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  1. GMAT
  2. GMT-1899

Beta Angle is Off by about .003 degrees

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      13 May 2010.

      See the script and truth data for test case CSparams_GMAT_ISS_2Body.script

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            gmatloj Linda Jun added a comment -

            Code matches with the math spec. Can you verify that truth data is correct?

            3.2.8 BetaAngle
            Definition: The Beta angle, β, is defined as the angle between the orbit normal vector, and the vector from the celestial body to the sun.

            ˆh = r⊕ × v⊕ / |r⊕ × v⊕k|
            ˆrs⊕ = rs⊕ / |s⊕|
            β = sin−1(ˆh · ˆrs⊕) (3.102)

            • r⊕: Position vector of spacecraft with respect to celestial body, in the EarthMJ2000Eq system.
            • v⊕: Velocity vector of spacecraft with respect to celestial body, in the EarthMJ2000Eq system.
            • rs⊕: Position vector from celestial body, to the sun.

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            gmatloj Linda Jun added a comment - Code matches with the math spec. Can you verify that truth data is correct? 3.2.8 BetaAngle Definition: The Beta angle, β, is defined as the angle between the orbit normal vector, and the vector from the celestial body to the sun. ˆh = r⊕ × v⊕ / |r⊕ × v⊕k| ˆrs⊕ = rs⊕ / |s⊕| β = sin−1(ˆh · ˆrs⊕) (3.102) • r⊕: Position vector of spacecraft with respect to celestial body, in the EarthMJ2000Eq system. • v⊕: Velocity vector of spacecraft with respect to celestial body, in the EarthMJ2000Eq system. • rs⊕: Position vector from celestial body, to the sun.
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            gmatloj Linda Jun added a comment -

            Joel,
            Can you verify that truth data is correct?

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            gmatloj Linda Jun added a comment - Joel, Can you verify that truth data is correct?
            Hide
            jjkparker Joel Parker added a comment -

            Truth data was incorrect. Tests are now matching.

            Show
            jjkparker Joel Parker added a comment - Truth data was incorrect. Tests are now matching.

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